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Help with RSGB mock exam question please

› Forums › Foundation Online Discussion › Help with RSGB mock exam question please

  • This topic has 3 replies, 2 voices, and was last updated 2 months, 1 week ago by Pete Sipplepetes.
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  • 11/05/2026 at 12:41 PM #3599
    Kathleen EngleKath
    Participant

      Hello Pete,

      I’m struggling with question 9 on the RSGB mock test three. It is a circuit diagram.

      Both C and D look correct to me. The answer key shows that D is correct.

      When I build it on DC circuit builder it shows both are the same.

      Please can you explain why C is incorrect? I’m clearly missing something.

      Thank you,
      Kath

      11/05/2026 at 4:44 PM #3601
      Pete Sipplepetes
      Keymaster

        No problem, and yes, this is a messy one.

        You can remove R1 and R2 as red herrings.

        Essentially, you’re left with the standard “parallel” drawing from the course – this one:

        https://www.essexham.co.uk/courseimg/circuit-parallel_5dee3982d6999.png

        Where a power supply feeds more than one component (e.g. two lamps, or in this case, 2 resistors), the voltage is the same, and the supplied current is the sum of the currents through the individual components.

        Just like the example in the course, each lamp has a direct connection, so each gets the full voltage. Half of the circuit’s total current flows through each of the two bulbs.

        Correct answer is D – the current over R3 and R4 will be different (as they are different values), but the voltage across the circuit will be the same. It it was a 3 volt battery, all four resistors would have 3v going across them, but different currents.

        Does that help?

        Pete

        11/05/2026 at 9:13 PM #4074
        Kathleen EngleKath
        Participant

          Hi Pete,
          Yes, it makes perfect sense to me now.
          Thank you very much!
          Kath

          12/05/2026 at 4:47 PM #4096
          Pete Sipplepetes
          Keymaster

            Cool. Happy to help.

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